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Exam Code: AD0-E207 Dumps

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NEW QUESTION: 1
Refer to the exhibit. The network is converged.After link-state advertisements are received from Router_A, what information will Router_E contain in its routing table for the subnets
208.149.23.64 and 208.149.23.96?

A. 208.149.23.64[110/13] via 190.173.23.10, 00:00:07, FastEthemet0/0 208.149.23.96[110/13] via
190.173.23.10, 00:00:16, FastEthemet0/0
B. 208.149.23.64[110/13] via 190.173.23.10, 00:00:07, Serial1/0 208.149.23.96[110/13] via 190.173.23.10,
00:00:16, Serial1/0 208.149.23.96[110/13] via 190.173.23.10, 00:00:16, FastEthemet0/0
C. 208.149.23.64[110/1] via 190.172.23.10, 00:00:07, Serial1/0 208.149.23.96[110/3] via 190.173.23.10,
00:00:16, FastEthemet0/0
D. 208.149.23.64[110/3] via 190.172.23.10, 00:00:07, Serial1/0 208.149.23.96[110/3] via 190.173.23.10,
00:00:16, Serial1/0
Answer: A
Explanation:
Router_E learns two subnets subnets 208.149.23.64 and 208.149.23.96 via Router_A through FastEthernet interface. The interface cost is calculated with the formula 108 / Bandwidth. For FastEthernet it is 108 / 100 Mbps = 108 / 100,000,000 = 1.
Therefore the cost is 12 (learned from Router_A) + 1 = 13 for both subnets -> The cost through T1 link is much higher than through T3 link (T1 cost = 108 / 1.544 Mbps = 64; T3 cost = 108 / 45 Mbps = 2) so surely OSPF will choose the path through T3 link -> Router_E will choose the path from Router_A through FastEthernet0/0, not Serial1/0.
In fact, we can quickly eliminate answers B, C and D because they contain at least one subnet learned from Serial1/0 -> they are surely incorrect.

NEW QUESTION: 2

A. Option A
B. Option B
C. Option C
D. Option D
Answer: C
Explanation:


NEW QUESTION: 3
Refer to the exhibit.

Given the output shown from this Cisco Catalyst 2950, what is the reason that interface FastEthernet
0/10 is not the root port for VLAN 2?
A. This switch is running RSTP while the elected designated switch is running 802.1d Spanning Tree.
B. This switch has a lower bridge ID for VLAN 2 than the elected designated switch.
C. This switch has more than one interface connected to the root network segment in VLAN 2.
D. This switch interface has a higher path cost to the root bridge than another in the topology.
Answer: D
Explanation:
Since the port is in the blocked status, we must assume that there is a shorter path to the bridge elsewhere.


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