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NEW QUESTION: 1
An organization wants to replace its suite of legacy applications with a new, in-house developed solution.
Which of the following is the BEST way to address concerns associated with migration of all mission-critical business functionality?
A. Plan multiple releases to gradually migrate subsets of functionality to reduce production risk.
B. Increase testing efforts so that all possible combinations of data have been tested prior to go-live.
C. Strengthen governance by hiring certified and qualified project managers for the migration.
D. Expedite go-live by migrating in a single release to allow more time for testing in production.
Answer: A
NEW QUESTION: 2
매일 수백만 건의 거래를 처리하는 금융 기관에는 ATM (automated teller machine)에 연결하기위한 중앙 통신 프로세서 (스위치)가 있습니다. 다음 중 통신 프로세서를위한 최상의 비상 계획은 무엇입니까?
A. 다른 조직과의 상호 계약
B. 이중 통신 링크 설치
C. 같은 위치에있는 대체 프로세서
D. 다른 네트워크 노드의 대체 프로세서
Answer: D
Explanation:
설명:
중앙 통신 프로세서를 사용할 수 없으면 은행 네트워크에 대한 모든 액세스가 중단됩니다. 이는 장비, 전원 또는 통신 장애로 인해 발생할 수 있습니다. 상 호 합의는 조직을 다른 조직에 의존하게하고 개인 정보, 경쟁 및 규제 문제를 제기합니다. 동일한 위치에 대체 프로세서를두면 장비 문제는 해결되지만, 장애가 환경 조건 (예 : 정전)으로 인해 발생한 경우에는 효과가 없습니다. 이중 통신 링크의 설치는 장애가 통신 링크에만 국한되어있는 경우에만 적합합니다.
NEW QUESTION: 3
An audit engagement objective at a manufacturer is to determine the quality of raw materials purchased.
Which of the following actions would best enable an internal auditor to satisfy this objective?
A. Research the rationale for customer returns.
B. Analyze the provision for sales allowances.
C. Analyze the percentage of scrap incurred during production.
D. Evaluate the volume and characteristics of products rejected during processing.
Answer: D
NEW QUESTION: 4
Given the fragment:
Which code fragment when inserted at line '// insert code fragment here', enables the code to successfully change array elements to uppercase?
A. String[][] arra = new String[3][];
arra[0] = new String[]{"rose", "lily"};
arra[1] = new String[]{"apple", "berry","cherry","grapes"};
arra[0] = new String[]{"beans", "carrot","potato"};
for (int i = 0; i < arra.length; i++) {
for (int j=0; j < arra[i].length; j++) {
arra[i][j] = arra[i][j].toUpperCase();
}
}
B. for (int i:arra.length) {
for (String x:arra) {
arra[i].toUpperCase();
}
}
C. for (String a[]:arra[][]) {
for (String x:a[]) {
x.toUpperCase();
}
}
D. for (int i = 0; i < 3; i++) {
for (int j=0; j < 4; j++) {
arra[i][j] = arra[i][j].toUpperCase();
}
}
Answer: C
Explanation:
Explanation/Reference:
Incorrect:
not A: arra.length is 3, but the subarrays have 2, 3 and 4 elements. Index will be out of bound.
not B: The subarrys are of different lengths. Index will be out of bound.
not D: Compile error.
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