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Vendor: Linux Foundation

Exam Code: CKS Dumps

Questions and Answers: 104

Product Price: $69.00

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NEW QUESTION: 1

A. Option D
B. Option A
C. Option B
D. Option C
Answer: B
Explanation:
Explanation
References https://docs.oracle.com/cd/B28359_01/network.111/b28531/auditing.htm#DBSEG0622

NEW QUESTION: 2
Review the analysis shown here.

Which statements are true about the process? (Note: There are 3 correct answers).
A. The process follows a non-normal distribution with the given data.
B. The process has more problems with Variation than Centering.
C. The initial focus for this project would be to determine why the thicknesses are so frequently too low.
D. This process is described with the Weibull Distribution.
E. The majority of the process is closer to the lower specification limit.
Answer: A,B,E

NEW QUESTION: 3
You administer a Microsoft SQL Server 2012 database named ContosoDb. Tables are defined as shown in the exhibit. (Click the Exhibit button.)

You need to display rows from the Orders table for the Customers row having the CustomerIdvalue set to 1 in the following XML format.

Which Transact-SQL query should you use?
A. SELECT Name, Country, Orderld, OrderDate, Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE Customers.CustomerId= 1 FOR XML AUTO, ELEMENTS
B. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers. CustomerId WHERE Customers=CustomerId = 1 FOR XML RAW, ELEMENTS
C. SELECT Name AS '@Name', Country AS '@Country', OrderId, OrderDate, Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE Customers.CustomerId= 1 FOR XML PATH ('Customers')
D. SELECT Name, Country, OrderId, OrderDate, Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE Customers.CustomerId= 1 FOR XML AUTO
E. SELECT Name AS 'Customers/Name', Country AS 'Customers/Country', OrderId, OrderDate, Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE Customers.CustomerId= 1 FOR XML PATH ('Customers')
F. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers. CustomerId WHERE Customers.CustomerId = 1 FOR XML AUTO
G. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers. CustomerId WHERE Customers.CustomerId = 1 FOR XML RAW
H. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId= 1 FOR XML AUTO, ELEMENTS
Answer: F
Explanation:
Reference: http://msdn.microsoft.com/en-us/library/ms188273.aspx

NEW QUESTION: 4
You create a mailbox named ConfRoom1 as shown in the exhibit. (Click the Exhibit button.)

Users report that when they schedule meetings and attempt to locate ConfRoom1 in the All Rooms address list, they do not see ConfRoom1 on the list.
You need to ensure that the users can locate ConfRoom1 on the All Rooms address list.
What should you do?
A. Modify the Sharing Policy that is associated to ConfRoom1.
B. Run the Update-AddressList command and specify the -Identity parameter.
C. Run the Set-Mailbox command and specify the -IsRootPublicFolderMailbox parameter.
D. Delete the ConfRoom1 mailbox, and create a new resource mailbox.
Answer: D


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