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NEW QUESTION: 1
Click the Exhibit button.
Based on the output in the exhibit, which statement is correct?
A. R4 has been configured with an IS-IS export policy and is announcing external routing information.
B. R3 and R4 have an adjacency at both level 1 and level 2.
C. R3 and R4 have only a level 2 adjacency.
D. R3 has been configured so that it is not used for transit traffic.
Answer: C
NEW QUESTION: 2
Click the Exhibit button.
{primarynode0}[edit security idp idp-policy test-ips-policy]
user@host# show
rulebase-ips {
rule r1 {
match {
source-address any;
attacks {
predefined-attack-groups "HTTP - All";
}
}
then {
action {
drop-packet;
}
}
terminal;
}
rule r2 {
match {
source-address 172.16.0.0/12;
attacks {
predefined-attack-groups "FTP - All";
}
then {
action {
no-action;
}
}
}
rule r3 {
match {
source-address 172.16.0.0/12;
attacks {
predefined-attack-groups "TELNET - All";
}
}
then {
action {
no-action;
}
}
}
rule r4 {
match {
source-address any;
attacks {
predefined-attack-groups "FTP - All";
}
}
then {
action {
drop-packet;
}
}
}
}
A user with IP address 172.301.100 initiates an FTP session to a host with IP address 10.100.1.50 through an SRX Series device and is subject to the IPS policy shown in the exhibit.
cd ~root command, which statement is correct?
If the user tries to execute the
A. The FTP command will be denied with the offending packet dropped and the session will be closed by the SRX device.
B. The FTP command will be allowed to execute and the rest of the FTP session will be ignored by the IPS policy.
C. The FTP command will be allowed to execute but any other attacks executed during the session will be inspected.
D. The FTP command will be denied with the offending packet dropped and the rest of the FTP session will be inspected by the IPS policy.
Answer: C
NEW QUESTION: 3
What is the behavior of the default partitioner?
A. The default partitioner computes the hash of the key. Hash values between specific ranges are associated with different buckets, and each bucket is assigned to a specific reducer.
B. The default partitioner implements a round robin strategy, shuffling the key value pairs to each reducer in turn. This ensures an even partition of the key space.
C. The default partitioner computes the hash of the key and divides that value modulo the number of reducers. The result determines the reducer assigned to process the key-value pair.
D. The default partitioner assigns key value pairs to reducers based on an internal random number generator.
E. The default partitioner computes the hash of the value and takes the mod of that value with the number of reducers. The result determines the reducer assigned to process the key value pair.
Answer: C
Explanation:
The default partitioner computes a hash value for the key and assigns the partition based on this result.
The default Partitioner implementation is called HashPartitioner. It uses the hashCode() method of the key objects modulo the number of partitions total to determine which partition to send a given (key, value) pair to.
In Hadoop, the default partitioner is HashPartitioner, which hashes a record's key to determine which partition (and thus which reducer) the record belongs in.The number of partition is then equal to the number of reduce tasks for the job.
Reference:Getting Started With (Customized) Partitioning
NEW QUESTION: 4
Given the code fragment:
Which modification enables the code fragment to print TrueDone?
A. Replace line 5 With String opt = "true";Replace line 7 with case "true":
B. Remove the default section.
C. Replace line 5 with boolean opt = l;Replace line 7 with case 1:
D. At line 9, remove the break statement.
Answer: A
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