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Vendor: CompTIA

Exam Code: CS0-003 Dumps

Questions and Answers: 104

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NEW QUESTION: 1
What is a continuous protection feature of Advanced Malware Protection?
A. Global ThreatIntelligence
B. Behavioral Indicators of Compromise
C. Sandboxing File Analysis
D. File Reputation
Answer: A

NEW QUESTION: 2
You are implementing an ASP.NET Web site. The site contains the following class.
public class Address
{ public int AddressType; public string Line1; public string Line2; public string City; public string ZipPostalCode;
}
The Web site interacts with an external data service that requires Address instances to be given in the following XML format.
<Address AddressType="2"> <Line1>250 Race Court</Line1> <City>Chicago</City> <ZipCode>60603</ZipCode>
</Address>
You need to ensure that Address instances that are serialized by the XmlSerializer class meet the XML
format requirements of the external data service.
Which two actions should you perform (Each correct answer presents part of the solution. Choose two.)
A. Add the following attribute to the ZipPostalCode field.
[XmlElement("ZipCode")]
B. Add the following attribute to the ZipPostalCode field.
[XmlAttribute("ZipCode")]
C. Add the following attribute to the AddressType field.
[XmlAttribute]
D. Add the following attribute to the Line2 field.
[XmlElement(IsNullable=true)]
Answer: A,C

NEW QUESTION: 3





A. CREATE TRIGGER TrgVwEmployee ON VwEmployee FOR INSERT AS BEGIN INSERT INTO Person(Id, FirstName, LastName) SELECT Id, FirstName, LastName, FROM inserted INSERT INTO Employee(PersonId, EmployeeNumber) SELECT Id, EmployeeNumber FROM inserted END
B. CREATE TRIGGER TrgVwEmployee ON VwEmployee
INSTEAD OF INSERT
AS
BEGIN
DECLARE @ID INT, @FirstName NVARCHAR(25), @LastName NVARCHAR(25),
@PersonID INT,
@EmployeeNumber NVARCHAR(15)
SELECT @ID = ID, @FirstName = FirstName, @LastName = LastName,
@EmployeeNumber =
EmployeeNumber
FROM inserted
INSERT INTO Person(Id, FirstName, LastName)
VALUES(@ID, @FirstName, @LastName)
INSERT INTO Employee(PersonID, EmployeeNumber)
VALUES(@PersonID, @EmployeeNumber
End
C. CREATE TRIGGER TrgVwEmployee ON VwEmployee INSTEAD OF INSERT AS BEGIN INSERT INTO Person(Id, FirstName, LastName) SELECT Id, FirstName, LastName FROM VwEmployee INSERT INTO Employee(PersonID, EmployeeNumber) SELECT Id, EmployeeNumber FROM VwEmployee End
D. CREATE TRIGGER TrgVwEmployee ON VwEmployee INSTEAD OF INSERT AS BEGIN INSERT INTO Person(Id, FirstName, LastName) SELECT Id, FirstName, LastName, FROM inserted INSERT INTO Employee(PersonId, EmployeeNumber) SELECT Id, EmployeeNumber FROM inserted END
Answer: D


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