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Exam Code: C_CPE_2409 Dumps

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NEW QUESTION: 1
ABC has created a multi-tenant Learning Management System (LMS). The application is hosted for five different tenants (clients) in the VPCs of the respective AWS accounts of the tenant. ABC wants to setup a centralized server which can connect with the LMS of each tenant upgrade if required. ABC also wants to ensure that one tenant VPC should not be able to connect to the other tenant VPC for security reasons.
How can ABC setup this scenario?
A. ABC has to setup one centralized VPC which will peer in to all the other VPCs of the tenants.
B. ABC should setup VPC peering with all the VPCs peering each other but block the IPs from CIDR of the tenant VPCs to deny them.
C. ABC should setup all the VPCs meshed together with VPC peering for all VPCs.
D. ABC should setup all the VPCs with the same CIDR but have a centralized VPC. This way only the centralized VPC can talk to the other VPCs using VPC peering.
Answer: A
Explanation:
Explanation
A Virtual Private Cloud (VPC) is a virtual network dedicated to the user's AWS account. It enables the user to launch AWS resources into a virtual network that the user has defined. A VPC peering connection allows the user to route traffic between the peer VPCs using private IP addresses as if they are a part of the same network.
This is helpful when one VPC from the same or different AWS account wants to connect with resources of the other VPC. The organization wants to setup that one VPC can connect with all the other VPCs but all other VPCs cannot connect among each other. This can be achieved by configuring VPC peering where one VPC is peered with all the other VPCs, but the other VPCs are not peered to each other. The VPCs are in the same or a separate AWS account and should not have overlapping CIDR blocks.
http://docs.aws.amazon.com/AmazonVPC/latest/PeeringGuide/peering-configurations-full-access.html#many-vp

NEW QUESTION: 2
DRAG DROP


Answer:
Explanation:


NEW QUESTION: 3
プロジェクトに関係者を参加させるインターネットサイトの作成は、どのタイプのコミュニケーションの例ですか?
A. インタラクティブ
B. 反復
C. プッシュ
D. プル
Answer: D

NEW QUESTION: 4
Refer to the exhibit.

Which configuration prevents R2 from becoming a PIM neighbor with R1?
A. access-list 10 deny 192.168.1.2 0.0.0.0 ! Interface gi0/0 ip pim neighbor-filter 1
B. access-list 10 deny 192.168.1.2 0.0.0.0 ! Interface gi0/0 ip igmp access-group 10
C. access-list 10 permit 192.168.1.2 0.0.0.0 ! Interface gi0/0 ip pim neighbor-filter 10
D. access-list 10 deny 192.168.1.2 0.0.0.0 ! Interface gi0/0 ip pim neighbor-filter 10
Answer: D


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