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Vendor: Palo Alto Networks

Exam Code: CloudSec-Pro Dumps

Questions and Answers: 104

Product Price: $69.00

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NEW QUESTION: 1
An organization manages their sales process and tracks their competitors on opportunities through Microsoft Dynamics 365.
A sales executive requests a report on how they are performing against each of their competitors.
Using only out-of-box capabilities, how should you get this report for the sales executive?
A. Add the Power BI content pack for Sales Managers, and share it with the executive.
B. Create a dashboard with the chart editor and include the competitors' details, and share it with the sales executive.
C. On a view of opportunities, run the Pipeline Management Excel Template.
D. Run the built-in Competitor Win/Loss report, and send it to the sales executive.
Answer: D
Explanation:
Explanation
References:
https://www.microsoft.com/en-us/dynamics/crm-customer-center/competitor-win-loss-report.aspx

NEW QUESTION: 2
An administrator needs to limit the size of the filesystem cache. Which tuning parameters need to be adjusted?
A. sb_min and sb_max
B. minfree and maxfree
C. minpgahead and maxpgahead
D. minperm and maxperm
E. minfreemem and maxfreemem
Answer: D

NEW QUESTION: 3

A. Option B
B. Option C
C. Option D
D. Option A
E. Option E
Answer: A,C

NEW QUESTION: 4
What happens when you attempt to compile and run the following code?
# include <deque>
# include <iostream>
# include <algorithm>
# include <functional>
using namespace std;
class B { int val;
public:
B(int v):val(v){}
int getV() const {return val;} bool operator > (const B & v) const { return val>v.val;} }; ostream & operator <<(ostream & out, const B & v) { out<<v.getV(); return out;} template<class T>struct Out {
ostream & out; Out(ostream & o): out(o){}
void operator() (const T & val ) { out<<val<<" "; } };
int main() {
int t[]={20, 30, 10, 20, 30, 10, 20, 30, 10, 20};
deque<B> d1(t, t+10);
sort(d1.begin(), d1.end(), greater<B>());
pair<deque<B> ::iterator, deque<B>::iterator > result = equal_range(d1.begin(), d1.end(),
B(20), greater<B>());
for_each(result.first, result.second, Out<B>(cout));cout<<endl;
return 0;
}
Program outputs:
A. 30 20 20 20 10
B. 20 20 20 20
C. 30 20 20 20 20 10
D. 20 20 20 20 10
E. 30 30 30 20 20 20 20 10 10 10
Answer: B


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