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NEW QUESTION: 1
Exhibit:
A network administrator is migrating from IPv4 to IPv6 and one of the IS-IS adjacencies is not coming up between R1 and R2.
Which action will solve the problem?
A. Remove topologies ipv6-unicast from protocols isis on R1.
B. Configure an IPv4 address on interface ge-0/0/1 on R1.
C. Configure topologies ipv4-unicast from protocols isis on R2.
D. Remove topologies ipv6-unicast from protocols isis on R2.
Answer: B
NEW QUESTION: 2
개발자는 Amazon DynamoDB 테이블에서 수억 개의 제품 리뷰를 추적하는 응용 프로그램을 개발하고 있습니다. 레코드에는 표에 표시된 데이터 요소가 포함됩니다.
어떤 필드를 파티션 키로 사용하면 DynamoDB를 사용하여 일관된 성능을 유지할 수 있습니까?
A. 의견
B. starRating
C. 제품 ID
D. 리뷰 ID
Answer: C
Explanation:
설명
AWS 설명서 참조 - DynamoDB Design 파티션 키
테이블의 기본 키의 파티션 키 부분은 테이블의 데이터가 저장되는 논리적 파티션을 결정합니다. 이것은 차례로 기본 물리적 파티션에 영향을줍니다. 테이블의 프로비저닝 된 I / O 용량은 이러한 물리적 파티션간에 균등하게 나뉩니다. 따라서 I / O 요청을 고르게 분산시키지 않는 파티션 키 디자인은 제한된 결과를 초래하는 "핫"파티션을 만들어 프로비저닝 된 I / O 용량을 비효율적으로 사용합니다.
테이블의 프로비저닝 된 처리량을 최적으로 사용하는 것은 개별 항목의 작업량 패턴뿐만 아니라 파티션 키 디자인에도 달려 있습니다. 이것은 효율적인 처리량 레벨을 얻기 위해 모든 파티션 키 값에 액세스해야하거나 액세스 된 파티션 키 값의 백분율이 높아야한다는 의미는 아닙니다. 이는 워크로드가 액세스하는 구별 된 파티션 키 값이 많을수록 요청이 파티션 된 공간에 더 많이 분산된다는 것을의 L합니다. 일반적으로 액세스 된 파티션 키 값의 비율이 파티션 키 값의 총 수로 증가함에 따라 프로비저닝 된 처리량을보다 효율적으로 사용하게됩니다.
NEW QUESTION: 3
Which statement about the Save Translation command is true?
A. It writes a copy for translation data to the hard drive.
B. It writes a copy for translation data to the FTP Server.
C. It runs automatically after every SAT command.
D. It writes a copy for translation data to RAM memory.
Answer: A