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NEW QUESTION: 1
개발자가 Amazon DynamoDB 테이블에서 global secondary index의 항목 목록을 찾으려고 합니다. 가장 적은 수의 읽기 용량 단위를 소비하기 위해 개발자가 사용할 수 있는 DynamoDB API 호출은 무엇입니까?
A. 일관성 있는 읽기를 사용하는 쿼리 작업
B. 최종 일관성 있는 읽기를 사용한 스캔 작업
C. 최종 일관성 있는 읽기를 사용하는 쿼리 작업
D. 일관된 읽기를 사용한 스캔 작업
Answer: C
Explanation:
Explanation
https://docs.aws.amazon.com/amazondynamodb/latest/developerguide/bp-query-scan.html
NEW QUESTION: 2
Which statement is true regarding Travel Areas in OFSC?
A. A given work zone can be assigned to multiple Travel Areas.
B. Travel Areas define a company's serviceable geography and are made up of groups of work zones.
C. Statistics are calculated using the travels between Travel Areas.
D. A Travel Area can be assigned to a bucket or a resource.
E. Travel between work zones within different Travel Areas will not be calculated for statistical use.
Answer: B
Explanation:
Explanation
Reference
https://docs.oracle.com/cloud/february2017/fieldservicecs_gs/FAADU/Administration.htm#FAADUViewTravel
NEW QUESTION: 3
Refer to the exhibit. The network is converged.After link-state advertisements are received from Router_A, what information will Router_E contain in its routing table for the subnets 208.149.23.64 and
208.149.23.96?
A. 208.149.23.64[110/1]via190.172.23.10,00:00:07, Serial1/0208.149.23.96[110/3]via190.173.23.10,
00:00:16, FastEthemet0/0
B. 208.149.23.64[110/13]via190.173.23.10,00:00:07, FastEthemet0/0208.149.23.96[110/13]via
190.173.23.10, 00:00:16, FastEthemet0/0
C. 208.149.23.64[110/3]via190.172.23.10,00:00:07, Serial1/0208.149.23.96[110/3]via190.173.23.10,
00:00:16, Serial1/0
D. 208.149.23.64[110/13]via190.173.23.10,00:00:07, Serial1/0208.149.23.96[110/13]via
190.173.23.10,
00:00:16, Serial1/0 208.149.23.96[110/13] via 190.173.23.10, 00:00:16, FastEthemet0/0
Answer: B
Explanation:
Explanation/Reference:
Explanation:
Router_E learns two subnets subnets 208.149.23.64 and 208.149.23.96 via Router_A through FastEthernet interface. The interface cost is calculated with the formula 108 / Bandwidth. For FastEthernet it is 108 / 100 Mbps = 108 / 100,000,000 = 1. Therefore, the cost is 12 (learned from Router_A) + 1 = 13 for both subnets -> The cost through T1 link is much higher than through T3 link (T1 cost = 108 / 1.544 Mbps = 64; T3 cost
108 / 45 Mbps = 2) so surely OSPF will choose the path through T3 link -> Router_E will choose the path from Router_A through FastEthernet0/0, not Serial1/0. In fact, we can quickly eliminate answers B, C and D because they contain at least one subnet learned from Serial1/0 -> they are surely incorrect.
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