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NEW QUESTION: 1
Which two statements about stateless firewalls are true? (Choose two.)
A. They compare the 5-tuple of each incoming packet against configurable rules.
B. Cisco IOS cannot implement them because the platform is stateful by nature.
C. They are designed to work most efficiently with stateless protocols such as HTTP or HTTPS.
D. The Cisco ASA is implicitly stateless because it blocks all traffic by default.
E. They cannot track connections.
Answer: A,E
Explanation:
Explanation
In stateless inspection, the firewall inspects a packet to determine the 5-tuple--source and destination IP
addresses and ports, and protocol--information contained in the packet. This static information is then
compared against configurable rules to determine whether to allow or drop the packet.
In stateless inspection the firewall examines each packet individually, it is unaware of the packets that have
passed through before it, and has no way of knowing if any given packet is part of an existing connection, is
trying to establish a new connection, or is a rogue packet.
Source:
http://www.cisco.com/c/en/us/td/docs/wireless/asr_5000/19-0/XMART/PSF/19-PSF-Admin/19-PSF-
Admin_chapter_01.html
NEW QUESTION: 2
A. Option A
B. Option D
C. Option C
D. Option B
Answer: A
NEW QUESTION: 3
View the Exhibit and examine the structure in the DEPARTMENTS tables. (Choose two.) Examine this SQL statement:
SELECT department_id "DEPT_ID", department_name, 'b' FROM
departments
WHERE departments_id=90
UNION
SELECT department_id, department_name DEPT_NAME, 'a' FROM
departments
WHERE department_id=10
Which two ORDER BY clauses can be used to sort output?
A. ORDER BY 3;
B. ORDER BY DEPT_ID;
C. ORDER BY 'b';
D. ORDER BY DEPT_NAME;
Answer: A,B
NEW QUESTION: 4
Which two statements describe the IP address 10.16.3.65/23? (Choose two.)
A. The broadcast address of the subnet is 10.16.3.255 255.255.254.0.
B. The lowest host address in the subnet is 10.16.2.1 255.255.254.0.
C. The last valid host address in the subnet is 10.16.2.254 255.255.254.0
D. The subnet address is 10.16.3.0 255.255.254.0.
E. The network is not subnetted.
Answer: A,B
Explanation:
The mask 255.255.254.0 (/23) used with a Class A address means that there are 15 subnet bits and 9 host bits. The block size in the third octet is 2 (256 - 254). So this makes the subnets in 0, 2, 4, 6, etc., all the way to 254. The host 10.16.3.65 is in the 2.0 subnet.
The next subnet is 4.0, so the broadcast address for the 2.0 subnet is 3.255. The valid host addresses are 2.1 through 3.254
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