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Exam Code: HP2-I77 Dumps

Questions and Answers: 104

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NEW QUESTION: 1

A. Option D
B. Option B
C. Option C
D. Option A
Answer: D
Explanation:
Explanation
References https://docs.oracle.com/cd/B28359_01/network.111/b28531/auditing.htm#DBSEG0622

NEW QUESTION: 2
Review the analysis shown here.

Which statements are true about the process? (Note: There are 3 correct answers).
A. The majority of the process is closer to the lower specification limit.
B. The initial focus for this project would be to determine why the thicknesses are so frequently too low.
C. This process is described with the Weibull Distribution.
D. The process has more problems with Variation than Centering.
E. The process follows a non-normal distribution with the given data.
Answer: A,D,E

NEW QUESTION: 3
You administer a Microsoft SQL Server 2012 database named ContosoDb. Tables are defined as shown in the exhibit. (Click the Exhibit button.)

You need to display rows from the Orders table for the Customers row having the CustomerIdvalue set to 1 in the following XML format.

Which Transact-SQL query should you use?
A. SELECT Name, Country, Orderld, OrderDate, Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE Customers.CustomerId= 1 FOR XML AUTO, ELEMENTS
B. SELECT Name AS 'Customers/Name', Country AS 'Customers/Country', OrderId, OrderDate, Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE Customers.CustomerId= 1 FOR XML PATH ('Customers')
C. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId= 1 FOR XML AUTO, ELEMENTS
D. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers. CustomerId WHERE Customers=CustomerId = 1 FOR XML RAW, ELEMENTS
E. SELECT Name, Country, OrderId, OrderDate, Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE Customers.CustomerId= 1 FOR XML AUTO
F. SELECT Name AS '@Name', Country AS '@Country', OrderId, OrderDate, Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE Customers.CustomerId= 1 FOR XML PATH ('Customers')
G. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers. CustomerId WHERE Customers.CustomerId = 1 FOR XML RAW
H. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers. CustomerId WHERE Customers.CustomerId = 1 FOR XML AUTO
Answer: H
Explanation:
Reference: http://msdn.microsoft.com/en-us/library/ms188273.aspx

NEW QUESTION: 4
You create a mailbox named ConfRoom1 as shown in the exhibit. (Click the Exhibit button.)

Users report that when they schedule meetings and attempt to locate ConfRoom1 in the All Rooms address list, they do not see ConfRoom1 on the list.
You need to ensure that the users can locate ConfRoom1 on the All Rooms address list.
What should you do?
A. Run the Update-AddressList command and specify the -Identity parameter.
B. Run the Set-Mailbox command and specify the -IsRootPublicFolderMailbox parameter.
C. Modify the Sharing Policy that is associated to ConfRoom1.
D. Delete the ConfRoom1 mailbox, and create a new resource mailbox.
Answer: D


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