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NEW QUESTION: 1
Hinweis: Diese Frage ist Teil einer Reihe von Fragen, die dasselbe Szenario darstellen. Jede Frage in der Reihe enthält eine eindeutige Lösung, mit der die angegebenen Ziele erreicht werden können. Einige Fragensätze haben möglicherweise mehr als eine richtige Lösung, während andere möglicherweise keine richtige Lösung haben.
Nachdem Sie eine Frage in diesem Abschnitt beantwortet haben, können Sie NICHT mehr darauf zurückkommen. Infolgedessen werden diese Fragen nicht im Überprüfungsbildschirm angezeigt.
Ihr Netzwerk enthält eine Active Directory-Gesamtstruktur mit dem Namen contoso.com.
Sie müssen identifizieren, welcher Server der Schemamaster ist.
Lösung: Sie öffnen Active Directory-Benutzer und -Computer, klicken in der Konsolenstruktur mit der rechten Maustaste auf contoso.com und klicken dann auf Operations Master.
Erfüllt dies das Ziel?
A. Ja
B. Nein
Answer: A
Explanation:
Erläuterung
Sie müssen das Schema-Snap-In verwenden, um den Schemamaster zu finden. Das Schema-Snap-In wird nicht standardmäßig installiert, kann jedoch mithilfe von Schmmgmt.dll installiert werden.
Verweise:
https://www.petri.com/determining_fsmo_role_holders
NEW QUESTION: 2
A. Option D
B. Option A
C. Option B
D. Option E
E. Option F
F. Option C
Answer: C,D,F
Explanation:
An important feature of IPv6 is that it allows plug and play option to the network devices by allowing them to configure themselves independently. It is possible to plug a node into an IPv6 network without requiring any human intervention. This feature was critical to allow network connectivity to an increasing number of mobile devices. This is accomplished by autoconfiguration. IPv6 does not implement traditional IP broadcast, i.e. the transmission of a packet to all hosts on the attached link using a special broadcast address, and therefore does not define broadcast addresses. In IPv6, the same result can be achieved by sending a packet to the link-local all nodes multicast group at address ff02::1, which is analogous to IPv4 multicast to address 224.0.0.1.
NEW QUESTION: 3
In your schema, the DEPARTMENTS table contains the columns DEPARTMENT_ID and DEPARTMENT_NAME.
You want to display the department name for existing department id 10.
With SERVEROUTPUT enabled, which two blocks of code will give the required output?
A. DECLAREcv1 SYS_REFCURSOR;v_dept_name
departments.department_name%TYPE;BEGINEXECUTE IMMEDIATE 'BEGIN OPEN: cv1 FORSELECT department_name FROM departmnets WHERE department_id=10:
END;'USING IN cv1;FETCH cv1 INTO v_dept_name;DBMS_OUTPUT.PUT_LINE
(v_dept_name);CLOSE cv1;END;
B. DECLARETYPE dept_cur IS REF CURSOR;cv1 dept_cur;v_dept_name departments.
department_name%TYPE;BEGINOPEN cv1 FOR SELECT department_name FROM
departments WHERE department_id=10;IF cv1 IS NOT NULL THENFETCH cv1 INTO v_dept_name;DBMS_OUTPUT.PUT_LINE (v_dept_name);END IFCLOSE cv1;END;
C. DECLARETYPE names_t IS TABLE OF SYS_REFCURSOR INDEX BY
PLS_INTEGER;cv1 names_t;v_dept_name
departments.department_name%TYPE;BEGINOPEN cv1 FOR SELECT
department_name FROM departments WHERE department_id=10;FETCH cv1 INTO
v_dept_name;DBMS_OUTPUT.PUT_LINE (v_dept_name);CLOSE cv1;END;
D. DECLARETYPE dept_cur IS REF CURSOR RETURN departments%ROWTYPE;cv1
dept_cur;v_dept_name departments.department_name%TYPE;BEGINOPEN cv1 FOR SELECT * FROM departments WHERE department_id=10;FETCH cv1. department_name INTO v_dept_name;DBMS_OUTPUT.PUT_LINE (v_dept_name);CLOSE cv1;END;
Answer: A,C