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NEW QUESTION: 1
You administer an Azure environment that includes six Azure Resource Manager (ARM) virtual machines (VMs) that support development. The development team uses Azure SQL databases and Azure Queues for application storage. All Azure resources are grouped within a single subscription and resource group.
You need to reduce the recurring monthly Azure costs without degrading server performance. You must minimize the administrative effort involved.
What should you do?
A. Create an Azure Automation runbook that cycles the VMs daily.
B. Create an Azure PowerShell script that updates the VM size to Standard_A0 daily.
C. Update the development environment to use Azure Table storage.
D. Remove the development team role from the resource group daily.
Answer: C
NEW QUESTION: 2
Which two approaches optimize test maintenance and support future declarative configuration changes? Choose 2 answers.
A. Create a method that queries for valid records, then call this method within test methods.
B. Create a method that creates valid records,then call this method within test methods.
C. Create a method that performs a callout for valid records, then call this method within test methods.
D. Create a methods that loads valid Account records from a static resources, then call this method within test methods.
Answer: B,D
NEW QUESTION: 3
What are the benefits of HPOM? (Select three.)
A. improved software distribution
B. investment protection
C. reduced time to repair
D. improved quality of service
E. no agents management overhead
F. clearer silo separation
Answer: B,C,D
NEW QUESTION: 4
What happens when you attempt to compile and run the following code?
#include <iostream>
#include <string>
using namespace std;
class A {
public:
A() { cout << "A0 ";}
A(string s) { cout << "A1";}
};
class B : public A {
public:
B() { cout << "B0 ";}
B(string s) { cout << "B1 ";}
};
class C : private B {
public:
C() { cout << "C0 ";}
C(string s) { cout << "C1 ";}
};
int main () {
B b1;
C c1;
return 0;
}
A. It prints: B0 B1
B. It prints: A0 B0 A0 B0 C0
C. It prints: B0 B1 C0 C1
D. It prints: A0 B0 A0 B1 A0 C0 A0 C1
Answer: B
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