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Vendor: Juniper

Exam Code: JN0-481 Dumps

Questions and Answers: 104

Product Price: $69.00

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NEW QUESTION: 1
-- Exhibit --
{master}[edit]
user@router-RE0# run show task replication
Stateful Replication: Enabled
RE modE. Master
Protocol Synchronization Status
OSPF Complete
RIP Complete
BGP Complete
MPLS Complete
LDP Complete
{master}[edit]
user@router-RE0# run show bgp summary | match 192.168.1.1
1 92.168.1.1 65056 288 327 0 2 1:05 Establ
{backup}[edit]
user@router-RE1# run show system switchover
Graceful switchover: On
Configuration databasE. Ready
Kernel databasE. Ready
Peer statE. Steady State
{backup}[edit]
user@router-RE1# run show bgp summary | find 192.168.1.1
1 92.168.1.1 65056 592 737 3778 2 1:33 Establ
{backup}[edit]
user@router-RE1# run show bgp replication
Synchronization master:
Session statE. Up, SincE. 6d 20:42:51
Flaps: 1, Last flap reason: Commit-sync error
Protocol statE. Idle, SincE. 5d 19:41:52
Synchronization statE. Complete
Number of peers waitinG. AckWait: 0, SoWait: 0, ScheduleD. 0
rsync walk at: inet.0 - , queued 0
Messages sent: Open 1, Establish 7415, Update 17, Error , Complete 48
Messages receiveD. Open 1, Request 1 wildcard 47 targeted, EstablishAck 2827,
CompleteAck 4
-- Exhibit --
Click the Exhibit button.
Referring to the exhibit, which statement is correct?
A. An RE switchover is likely to result in BGP disruption, but no dataplane impact will be seen.
B. The system is not yet GRES ready, you need to wait for kernel synchronization to complete.
C. The system is NSR ready and a switchover should be hitless to the BGP control and data plane.
D. An RE switchover is likely to result in BGP disruption which will also effect the dataplane.
Answer: C

NEW QUESTION: 2
When the following code is compiled and run is a program what size block will be used to hold name string?
#include <stdio.h>
int main(int argc, char **argv)
{
char target[5]="TTTT";
char attacker[11]="AAAAAAAAAA";
strcpy(attacker, " DDDDDDDDDDDDDD");
printf("% \n", target);
return 0;
}
A. 28 bytes
B. 32 bytes
C. 8 bytes
D. 16 bytes
Answer: B

NEW QUESTION: 3
The MBR typically starts at sector:
A. 009FF00
B. 0
C. 09G94:99
D. 0090FEA
Answer: B


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