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NEW QUESTION: 1
The implementation group has been using the test bed to do an IPv6 'proof-of-concept1. After several changes to the network addressing and routing schemes, a trouble ticket has been opened indicating that the loopback address on R1 (2026::111:1) is not able to ping the loopback address on DSW2 (2026::102:1).
Use the supported commands to isolate the cause of this fault and answer the following question.
What is the solution to the fault condition?
A. Under the interface Tunnel34 configuration delete the tunnel source Serial0/0/0.34 command and enter the tunnel source 2026::34:1/122 command.
B. Under the interface Tunnel34 configuration enter the ip address unnumbered Serial0/0/0.34 command.
C. Under the interface Serial0/0/0.34 configuration enter the ipv6 address 2026::34:1/122 command.
D. Under the interface Tunnel34 configuration delete the tunnel mode ipv6 command.
Answer: D
Explanation:
As explained earlier, the problem is with route misconfigured tunnel modes on R3. R3 is using tunnel mode ipv6, while R4 is using the default of GRE. We need to remove the
"tunnel mode ipv6" command under interface Tunnel34
Case Study: 22
Lab EBGP and IBGP
NEW QUESTION: 2
A female client is started on warfarin (Coumadin) 5 mg po bid. To adequately evaluate the effectiveness of the warfarin therapy, the nurse must know that this medication:
A. Dissolves any clots already formed in the arteries
B. Stimulates the manufacturing of platelets
C. Prevents the conversion of prothrombin to thrombin
D. Interferes with the synthesis of vitamin K-dependent clotting factors
Answer: D
Explanation:
(A) Thrombolytic agents (e.g., streptokinase) directly activate plasminogen, dissolving fibrin deposits, which in turn dissolves clots that have already formed. (B) Heparin prevents the formation of clots by potentiating the effects of antithrombin III and the conversion of prothrombin to thrombin. (C) Warfarin prevents the formation of clots by interfering with the hepatic synthesis of the vitamin K-dependent clotting factors. (D) Platelets initiate the coagulation of blood by adhering to each other and the site of injury to form platelet plugs.
NEW QUESTION: 3
A user has configured two security groups which allow traffic as given below:
1: SecGrp1:
Inbound on port 80 for 0.0.0.0/0
Inbound on port 22 for 0.0.0.0/0
2: SecGrp2:
Inbound on port 22 for 10.10.10.1/32
If both the security groups are associated with the same instance, which of the below mentioned statements is true?
A. It allows inbound traffic on port 22 for IP 10.10.10.1 and for everyone else on port 80
B. It is not possible to have more than one security group assigned to a single instance
C. It allows inbound traffic for everyone on both ports 22 and 80
D. It is not possible to create the security group with conflicting rules. AWS will reject the request
Answer: C
Explanation:
Explanation
A user can attach more than one security group to a single EC2 instance. In this case, the rules from each security group are effectively aggregated to create one set of rules. AWS uses this set of rules to determine whether to allow access or not. Thus, here the rule for port 22 with IP 10.10.10.1/32 will merge with IP
0.0.0.0/0 and open ports 22 and 80 for all.
References:
NEW QUESTION: 4
Which of the following terms can be described as the process to conceal data into another file or media in a practice known as security through obscurity?
A. Encryption
B. NTFS ADS
C. Steganography
D. ADS - Alternate Data Streams
Answer: C
Explanation:
It is the art and science of encoding hidden messages in such a way that no one, apart from the sender and intended recipient, suspects the existence of the message or could claim there is a message.
It is a form of security through obscurity.
The word steganography is of Greek origin and means "concealed writing." It combines the
Greek words steganos (), meaning "covered or protected," and graphei () meaning
"writing."
The first recorded use of the term was in 1499 by Johannes Trithemius in his
Steganographia, a treatise on cryptography and steganography, disguised as a book on magic. Generally, the hidden messages will appear to be (or be part of) something else:
images, articles, shopping lists, or some other cover text. For example, the hidden message may be in invisible ink between the visible lines of a private letter.
The advantage of steganography over cryptography alone is that the intended secret message does not attract attention to itself as an object of scrutiny. Plainly visible encrypted messages, no matter how unbreakable, will arouse interest, and may in themselves be incriminating in countries where encryption is illegal. Thus, whereas cryptography is the practice of protecting the contents of a message alone, steganography is concerned with concealing the fact that a secret message is being sent, as well as concealing the contents of the message.
It is sometimes referred to as Hiding in Plain Sight. This image of trees blow contains in it another image of a cat using Steganography.
ADS Tree with Cat inside
This image below is hidden in the picture of the trees above:
Hidden Kitty
As explained here the image is hidden by removing all but the two least significant bits of each color component and subsequent normalization.
ABOUT MSF and LSF
One of the common method to perform steganography is by hiding bits within the Least
Significant Bits of a media (LSB) or what is sometimes referred to as Slack Space. By modifying only the least significant bit, it is not possible to tell if there is an hidden message or not looking at the picture or the media. If you would change the Most Significant Bits
(MSB) then it would be possible to view or detect the changes just by looking at the picture.
A person can perceive only up to 6 bits of depth, bit that are changed past the first sixth bit of the color code would be undetectable to a human eye.
If we make use of a high quality digital picture, we could hide six bits of data within each of the pixel of the image. You have a color code for each pixel composed of a Red, Green, and Blue value. The color code is 3 sets of 8 bits each for each of the color. You could change the last two bit to hide your data. See below a color code for one pixel in binary format. The bits below are not real they are just example for illustration purpose:
RED GREEN BLUE
0101 0101 1100 1011 1110 0011
MSB LSB MSB LSB MSB LSB
Let's say that I would like to hide the letter A uppercase within the pixels of the picture. If we convert the letter "A" uppercase to a decimal value it would be number 65 within the
ASCII table , in binary format the value 65 would translet to 01000001
You can break the 8 bits of character A uppercase in group of two bits as follow: 01 00 00
01
Using the pixel above we will hide those bits within the last two bits of each of the color as follow:
RED GREEN BLUE
0101 0101 1100 1000 1110 0000
MSB LSB MSB LSB MSB LSB
As you can see above, the last two bits of RED was already set to the proper value of 01, then we move to the GREEN value and we changed the last two bit from 11 to 00, and finally we changed the last two bits of blue to 00. One pixel allowed us to hide 6 bits of data. We would have to use another pixel to hide the remaining two bits.
The following answers are incorrect:
- ADS - Alternate Data Streams: This is almost correct but ADS is different from steganography in that ADS hides data in streams of communications or files while
Steganography hides data in a single file.
- Encryption: This is almost correct but Steganography isn't exactly encryption as much as using space in a file to store another file.
- NTFS ADS: This is also almost correct in that you're hiding data where you have space to do so. NTFS, or New Technology File System common on Windows computers has a feature where you can hide files where they're not viewable under normal conditions. Tools are required to uncover the ADS-hidden files.
The following reference(s) was used to create this question:
Steganography tool
and
http://en.wikipedia.org/wiki/Steganography
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