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It always considers the needs of customers in the development process.
NEW QUESTION: 1
ダイナミックARPインスペクションを設定しています。 Arpパケット内の予期しないIPアドレスを検出するには、どのコマンドをデバイスに設定する必要がありますか。
A. ip ARP検査がipを検証する
B. ip ARP検査VLAN
C. ip ARP検査信頼
D. ipソースの確認
Answer: A
NEW QUESTION: 2
LISPでサポートされている2つのコンポーネントはどれですか? (2つ選択してください)
A. スポーク
B. HMACアルゴリズム
C. 出力トンネルルーター
D. プロキシETR
E. ルートリフレクター
Answer: C,D
Explanation:
Explanation
https://www.cisco.com/c/en/us/td/docs/ios-xml/ios/iproute_lisp/configuration/xe-3s/irl-xe-3s-book/irl-overview.h
NEW QUESTION: 3
What are the variants of inventory procedure available in Warehouse Management? (Choose three)
A. Annual inventory
B. Continuous inventory
C. Inventory on first putaway
D. Quarterly inventory
Answer: A,B,C
NEW QUESTION: 4
You are a database developer for an application hosted on a Microsoft SQL Server 2012 server.
The database contains two tables that have the following definitions:
Global customers place orders from several countries.
You need to view the country from which each customer has placed the most orders.
Which Transact-SQL query do you use?
A. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
FROM
(SELECT c.CustomerID, c.CustomerName, o.ShippingCountry,
RANK() OVER (PARTITION BY CustomerID
ORDER BY COUNT(o.OrderAmount) ASC) AS Rnk
FROM Customer c
INNER JOIN Orders o
ON c.CustomerID = o.CustomerID
GROUP BY c.CustomerID, c.CustomerName, o.ShippingCountry) cs
WHERE Rnk = 1
B. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
FROM Customer c
INNER JOIN
(SELECT CustomerID, ShippingCountry,
RANK() OVER (PARTITION BY CustomerID
ORDER BY COUNT(OrderAmount) DESC) AS Rnk
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
WHERE o.Rnk = 1
C. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
FROM Customer c
INNER JOIN
(SELECT CustomerID, ShippingCountry,
COUNT(OrderAmount) DESC) AS OrderAmount
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
ORDER BY OrderAmount DESC
D. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
FROM Customer c
INNER JOIN
(SELECT CustomerID, ShippingCountry,
RANK() OVER (PARTITION BY CustomerID
ORDER BY OrderAmount DESC) AS Rnk
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
WHERE o.Rnk = 1
Answer: B