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NEW QUESTION: 1
The waters of the Antarctic region contain an abundance of animal and plant life. The large number of living organisms stems partly from the water's high mineral content and partly from the constant cold temperature. The continual flow of materials from below brings nitrates and phosphates into the surface zone. Cold water holds more dissolved carbon dioxide and oxygen than does warm water. The abundance of carbon dioxide and the available sunlight allow photosynthesis to occur in the surface waters almost continuously during the long daylight hours in the summer.
If the temperature of the Antarctic waters increased by a marked degree, which of the following statements would explain a decrease in the abundant life there now?
A. Warm water evaporates much more slowly than cold water.
B. Minerals dissolve more readily in cold water.
C. Warm water contains less dissolved carbon dioxide needed for photosynthesis.
D. In warm water, oxygen and carbon dioxide combine to form ammonia and other poisonous gases.
E. Warm water contains more oxygen than cold water.
Answer: C
NEW QUESTION: 2
コンビネーションロックのセキュリティレベルを決定するものは何ですか？
A. メタルロック材の硬度スコア
B. 組み合わせをブルートフォースするのにかかる時間
C. ロックを開くために必要な組み合わせの複雑さ
D. 内部メカニズムに関連付けられたバレルの数
Answer: C
NEW QUESTION: 3
Which two parameters are requested in an Audit Connection message from a Cisco Unified CM to endpoint on a MGCP gateway? (Choose two)
A. Capabilities
B. Connection ID
C. Connection Parameters
D. Bearer Information
E. Connection Mode
F. Call ID
Answer: C,F
Explanation:
NEW QUESTION: 4
This packet was taken from a packet sniffer that monitors a Web server.
This packet was originally 1514 bytes long, but only the first 512 bytes are shown here. This is the standard hexdump representation of a network packet, before being decoded. A hexdump has three columns: the offset of each line, the hexadecimal data, and the ASCII equivalent. This packet contains a 14-byte Ethernet header, a 20-byte IP header, a 20-byte TCP header, an HTTP header ending in two line-feeds (0D 0A 0D 0A) and then the data. By examining the packet identify the name and version of the Web server?
A. Linux WServer 2.3
B. IIS 4.0
C. IIS 5.0
D. Apache 1.2
Answer: B
Explanation:
We see that the server is Microsoft, but the exam designer didn't want to make it easy for you. So what they did is blank out the IIS 4.0. The key is in line "0B0" as you see:
0B0 69 63 72 6F 73 6F 66 74 2D 49 49 53 2F 34 2E 30 ..Microsoft
49 is I, so we get II
53 is S, so we get IIS
2F is a space
34 is 4
2E is .
30 is 0
So we get IIS 4.0
The answer is B
If you don't remember the ASCII hex to Character, there are enough characters and numbers already converted. For example, line "050" has STRIDER which is 53 54 52 49 44 45 52 and gives you the conversion for the "I:" and "S" characters (which is "49" and "53").
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