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Vendor: Palo Alto Networks

Exam Code: XDR-Analyst Dumps

Questions and Answers: 104

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NEW QUESTION: 1
An organization manages their sales process and tracks their competitors on opportunities through Microsoft Dynamics 365.
A sales executive requests a report on how they are performing against each of their competitors.
Using only out-of-box capabilities, how should you get this report for the sales executive?
A. On a view of opportunities, run the Pipeline Management Excel Template.
B. Add the Power BI content pack for Sales Managers, and share it with the executive.
C. Create a dashboard with the chart editor and include the competitors' details, and share it with the sales executive.
D. Run the built-in Competitor Win/Loss report, and send it to the sales executive.
Answer: D
Explanation:
Explanation
References:
https://www.microsoft.com/en-us/dynamics/crm-customer-center/competitor-win-loss-report.aspx

NEW QUESTION: 2
An administrator needs to limit the size of the filesystem cache. Which tuning parameters need to be adjusted?
A. minperm and maxperm
B. minfreemem and maxfreemem
C. minpgahead and maxpgahead
D. sb_min and sb_max
E. minfree and maxfree
Answer: A

NEW QUESTION: 3

A. Option A
B. Option B
C. Option D
D. Option E
E. Option C
Answer: B,C

NEW QUESTION: 4
What happens when you attempt to compile and run the following code?
# include <deque>
# include <iostream>
# include <algorithm>
# include <functional>
using namespace std;
class B { int val;
public:
B(int v):val(v){}
int getV() const {return val;} bool operator > (const B & v) const { return val>v.val;} }; ostream & operator <<(ostream & out, const B & v) { out<<v.getV(); return out;} template<class T>struct Out {
ostream & out; Out(ostream & o): out(o){}
void operator() (const T & val ) { out<<val<<" "; } };
int main() {
int t[]={20, 30, 10, 20, 30, 10, 20, 30, 10, 20};
deque<B> d1(t, t+10);
sort(d1.begin(), d1.end(), greater<B>());
pair<deque<B> ::iterator, deque<B>::iterator > result = equal_range(d1.begin(), d1.end(),
B(20), greater<B>());
for_each(result.first, result.second, Out<B>(cout));cout<<endl;
return 0;
}
Program outputs:
A. 20 20 20 20 10
B. 30 20 20 20 10
C. 30 30 30 20 20 20 20 10 10 10
D. 20 20 20 20
E. 30 20 20 20 20 10
Answer: D


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