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NEW QUESTION: 1
You are designing an n-tier Java EE application. You have already decided that some of your JSPs will need to get data from a Customer entity bean. You are trying to decide whether to use a Customer stub object or a Transfer Object. Which two statements are true? (Choose two.)
A. Using the stub approach allows you to design the application without using a Service
Locator.
B. The stub will increase network traffic.
C. Only the Transfer Object will need to use a Business Delegate.
D. The Transfer Object will decrease data staleness.
E. In both cases, the JSPs can use EL expressions to get data.
F. The stub will increase the logic necessary in the JSPs.
Answer: B,E
NEW QUESTION: 2
投資計画アプリケーションスイートのビルドエージェントとリリースエージェントはどこで実行する必要がありますか？ 回答するには、回答エリアで適切なオプションを選択します。
注：それぞれの正しい選択には1ポイントの価値があります。
Answer:
Explanation:
Explanation
Box 1: A source control system
A source control system, also called a version control system, allows developers to collaborate on code and track changes. Source control is an essential tool for multi-developer projects.
Box 2: A hosted service
To build and deploy Xcode apps or Xamarin.iOS projects, you'll need at least one macOS agent. If your pipelines are in Azure Pipelines and a Microsoft-hosted agent meets your needs, you can skip setting up a self-hosted macOS agent.
Scenario: The investment planning applications suite will include one multi-tier web application and two iOS mobile applications. One mobile application will be used by employees; the other will be used by customers.
References:
https://docs.microsoft.com/en-us/azure/devops/pipelines/agents/v2-osx?view=azure-devops
NEW QUESTION: 3
View the Exhibit and examine the structure of the SALES table.
The following query is written to retrieve all those product IDs from the SALES table that have more than
55000 sold and have been ordered more than 10 times.
Which statement is true regarding this SQL statement?
A. It executes successfully and generates the required result.
B. It produces an error because count(*) should be specified in the SELECT clause also.
C. It produces an error because count{*) should be only in the HAVING clause and not in the WHERE clause.
D. It executes successfully but produces no result because COUNT (prod_id) should be used instead of COUNT (*).
Answer: C
Explanation:
Explanation/Reference:
Explanation:
Restricting Group Results with the HAVING Clause
You use the HAVING clause to specify the groups that are to be displayed, thus further restricting the groups on the basis of aggregate information.
In the syntax, group_condition restricts the groups of rows returned to those groups for which the specified condition is true.
The Oracle server performs the following steps when you use the HAVING clause:
1. Rows are grouped.
2. The group function is applied to the group.
3. The groups that match the criteria in the HAVING clause are displayed.
The HAVING clause can precede the GROUP BY clause, but it is recommended that you place the GROUP BY clause first because it is more logical. Groups are formed and group functions are calculated before the HAVING clause is applied to the groups in the SELECT list.
Note: The WHERE clause restricts rows, whereas the HAVING clause restricts groups.
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